The observer is moving with velocity v_0 towa | vedclass

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(A) According to the Doppler effect,when the observer moves towards a stationary source with velocity $v_0$,the apparent frequency $n^{\prime}$ is giv

Vedclass · Accepted Answer

$\frac{2 n v_0}{v}$

Vedclass · Answer

(A) According to the Doppler effect,when the observer moves towards a stationary source with velocity $v_0$,the apparent frequency $n^{\prime}$ is given by $n^{\prime} = n \left( \frac{v + v_0}{v} \right)$.When the observer moves away from the stationary source with velocity $v_0$,the apparent frequency $n^{\prime \prime}$ is given by $n^{\prime \prime} = n \left( \frac{v - v_0}{v} \right)$.The difference between the apparent frequencies is $\Delta n = n^{\prime} - n^{\prime \prime}$.Substituting the values: $\Delta n = n \left( \frac{v + v_0}{v} \right) - n \left( \frac{v - v_0}{v} \right)$.$\Delta n = \frac{n}{v} (v + v_0 - v + v_0) = \frac{n}{v} (2 v_0) = \frac{2 n v_0}{v}$.

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