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(C) coordination compound is optically active if it lacks a plane of symmetry or a center of symmetry (i.e.,it is chiral).$1$. $[Cr(NH_3)_6]^{3+}$ is

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$[Co(gly)_3]$

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(C) coordination compound is optically active if it lacks a plane of symmetry or a center of symmetry (i.e.,it is chiral).$1$. $[Cr(NH_3)_6]^{3+}$ is an octahedral complex with six identical ligands,possessing multiple planes of symmetry. It is optically inactive.$2$. $[Co(CN)_6]^{3-}$ is an octahedral complex with six identical ligands,possessing multiple planes of symmetry. It is optically inactive.$3$. $[Ru(NH_3)_6]^{3+}$ is an octahedral complex with six identical ligands,possessing multiple planes of symmetry. It is optically inactive.$4$. $[Co(gly)_3]$ contains three bidentate glycinate $(gly^-)$ ligands. This complex exists as facial $(fac)$ and meridional $(mer)$ isomers. Both isomers lack a plane of symmetry and are chiral,making the species optically active.

The optically active species among the following is

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