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(C) To determine which molecules follow the Octet Rule,we check the valence electrons around the central atom:$1$. $CO_2$: $C$ has $8$ electrons (foll

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$A, D$

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(C) To determine which molecules follow the Octet Rule,we check the valence electrons around the central atom:$1$. $CO_2$: $C$ has $8$ electrons (follows octet).$2$. $C_2H_4$: $C$ has $8$ electrons (follows octet).$3$. $HCl$: $Cl$ has $8$ electrons (follows octet).$4$. $NO$: $N$ has $7$ electrons (odd electron molecule,violates octet).$5$. $NO_2$: $N$ has $7$ electrons (odd electron molecule,violates octet).$6$. $O_3$: Central $O$ has $8$ electrons (follows octet).$7$. $H_2SO_4$: $S$ has $12$ electrons (expanded octet,violates octet).$8$. $BCl_3$: $B$ has $6$ electrons (incomplete octet,violates octet).Evaluating options:$(A)$ $CO_2, C_2H_4, HCl$ follow octet ($3$ molecules). $NO$ does not.$(B)$ $O_3, HCl$ follow octet. $NO_2, H_2SO_4$ do not.$(C)$ $NO, NO_2, BCl_3, H_2SO_4$ do not follow octet.$(D)$ $CO_2, O_3, C_2H_4$ follow octet ($3$ molecules). $BCl_3$ does not.Thus,options $(A)$ and $(D)$ contain at least three molecules that follow the Octet Rule.

The option$(s)$ in which at least three molecules follow the Octet Rule is(are):
$(A)$ $CO_2, C_2H_4, NO$ and $HCl$
$(B)$ $NO_2, O_3, HCl$ and $H_2SO_4$
$(C)$ $BCl_3, NO, NO_2$ and $H_2SO_4$
$(D)$ $CO_2, BCl_3, O_3$ and $C_2H_4$

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The option$(s)$ in which at least three molecules follow the Octet Rule is(are):$(A)$ $CO_2, C_2H_4, NO$ and $HCl$$(B)$ $NO_2, O_3, HCl$ and $H_2SO_4$$(C)$ $BCl_3, NO, NO_2$ and $H_2SO_4$$(D)$ $CO_2, BCl_3, O_3$ and $C_2H_4$