The order of basicity among the following nit | vedclass

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Question

(D) The given compounds are: $(i)$ $C_6H_5CH_2NH_2$ (Benzylamine) (ii) $C_6H_5NHCH_3$ ($N$-methylaniline) (iii) $C_6H_5N(CH_3)_2$ ($N,N$-dimethylanili

Vedclass · Accepted Answer

$i > iii > ii > iv$

Vedclass · Answer

(D) The given compounds are: $(i)$ $C_6H_5CH_2NH_2$ (Benzylamine) (ii) $C_6H_5NHCH_3$ ($N$-methylaniline) (iii) $C_6H_5N(CH_3)_2$ ($N,N$-dimethylaniline) (iv) $C_6H_5NH_2$ (Aniline) Benzylamine $(i)$ is an aliphatic amine where the lone pair on nitrogen is not involved in resonance with the benzene ring,making it the most basic. Among the aryl amines (ii,iii,and iv),the basicity depends on the electron-donating effect of the methyl groups. $N,N$-dimethylaniline (iii) has two electron-donating methyl groups,making it more basic than $N$-methylaniline (ii),which has one methyl group. Aniline (iv) has no electron-donating methyl groups,making it the least basic. Thus,the correct order of basicity is $i > iii > ii > iv$.

The order of basicity among the following nitrogen compounds is:

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