The order of basicity of the compounds is

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(B) The compounds are: $(I)$ Piperidine,$(II)$ Pyridine,$(III)$ Morpholine,and $(IV)$ Pyrrole.In $(I)$,the nitrogen atom is $sp^3$ hybridized,and the

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$I > III > II > IV$

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(B) The compounds are: $(I)$ Piperidine,$(II)$ Pyridine,$(III)$ Morpholine,and $(IV)$ Pyrrole.In $(I)$,the nitrogen atom is $sp^3$ hybridized,and the lone pair is localized,making it highly basic.In $(III)$,the nitrogen atom is $sp^3$ hybridized,but the presence of an electronegative oxygen atom exerts an electron-withdrawing $-I$ effect,reducing its basicity compared to $(I)$.In $(II)$,the nitrogen atom is $sp^2$ hybridized,making the lone pair less available for protonation than in $sp^3$ hybridized amines.In $(IV)$,the lone pair on the nitrogen atom is involved in the aromatic sextet ($6\pi$ electrons),making it unavailable for protonation,thus it is the least basic.Therefore,the correct order of basicity is $(I) > (III) > (II) > (IV)$.

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