The order of electronegativity of carbon in s | vedclass

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(A) The electronegativity of a carbon atom is directly proportional to the $s$-character in its hybridised state. Greater $s$-character leads to highe

Vedclass · Accepted Answer

$sp > sp^{2} > sp^{3}$

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(A) The electronegativity of a carbon atom is directly proportional to the $s$-character in its hybridised state. Greater $s$-character leads to higher electronegativity because the electrons are held closer to the nucleus. The $s$-character in different hybridisations is as follows: $sp$: $50\% \ s$-character $sp^{2}$: $33.3\% \ s$-character $sp^{3}$: $25\% \ s$-character Therefore,the order of electronegativity is $sp > sp^{2} > sp^{3}$.

The order of electronegativity of carbon in $sp$,$sp^{2}$ and $sp^{3}$ hybridised states follows:

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