The order of equivalent conductances at infinite dilution for $LiCl$, $NaCl$, and $KCl$ is:

  • A
    $LiCl > NaCl > KCl$
  • B
    $KCl > NaCl > LiCl$
  • C
    $NaCl > KCl > LiCl$
  • D
    $LiCl > KCl > NaCl$

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Similar Questions

The resistance of a conductivity cell filled with $0.1 \ M$ $KCl$ solution is $100 \ \Omega$. If the resistance of the same cell when filled with $0.02 \ M$ $KCl$ solution is $520 \ \Omega$,the molar conductivity of $0.02 \ M$ solution (in $S \ cm^2 \ mol^{-1}$) is (Given: conductivity of $0.1 \ M$ $KCl$ solution $= 1.29 \ S \ m^{-1}$)

The number of correct statements from the following is $...........$.
$(A)$ Conductivity always decreases with decrease in concentration for both strong and weak electrolytes.
$(B)$ The number of ions per unit volume that carry current in a solution increases on dilution.
$(C)$ Molar conductivity increases with decrease in concentration.
$(D)$ The variation in molar conductivity is different for strong and weak electrolytes.
$(E)$ For weak electrolytes,the change in molar conductivity with dilution is due to decrease in degree of dissociation.

The distance between electrodes of a conductivity cell is $0.98 \ cm$ and area of cross section is $1.96 \ cm^{2}$. What is the cell constant (in $cm^{-1}$)?

Match List-$I$ with List-$II$:
List-$I$ (Parameter) List-$II$ (Unit)
$a$. Cell constant $i$. $S\, cm^{2}\, mol^{-1}$
$b$. Molar conductivity $ii$. Dimensionless
$c$. Conductivity $iii$. $m^{-1}$
$d$. Degree of dissociation of electrolyte $iv$. $\Omega^{-1}\, m^{-1}$

Choose the most appropriate answer from the options given below:

At $25^o C$, the molar conductivities at infinite dilution of $NaOAc$ and $HCl$ in water are $91.0 \, S \, cm^2/mol$ and $426.2 \, S \, cm^2/mol$, respectively. Which substance's molar conductivity must be subtracted to calculate the molar conductivity of $HOAc$ at infinite dilution?

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