What is the order of reactivity of the follow | vedclass

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(C) Sodalime decarboxylation involves the formation of a carbanion intermediate. The rate of decarboxylation is directly proportional to the stability

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$ii > i > iv > iii$

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(C) Sodalime decarboxylation involves the formation of a carbanion intermediate. The rate of decarboxylation is directly proportional to the stability of the carbanion formed. Electron-withdrawing groups $(EWG)$ stabilize the carbanion,while electron-donating groups $(EDG)$ destabilize it. The stability order of the carbanion intermediate is determined by the inductive effect ($-I$ effect) of the substituents. $(i)$ $m$-nitro group exerts a strong $-I$ effect. (ii) $p$-nitro group exerts a strong $-I$ effect. Since the $p$-position is closer to the reaction center in terms of inductive influence compared to the $m$-position in this specific structure,or considering the overall electron-withdrawing strength,the order is $ii > i$. (iii) $-OMe$ is an electron-donating group ($+M$ effect,though $-I$ at distance),which destabilizes the carbanion. (iv) $-CH_3$ is an electron-donating group ($+I$ effect),which also destabilizes the carbanion,but less than $-OMe$. Thus,the reactivity order is $ii > i > iv > iii$.

What is the order of reactivity of the following compounds towards sodalime decarboxylation?
$(i)$ $m$-nitro-phenylacetic acid
(ii) $p$-nitro-phenylacetic acid
(iii) $p$-methoxy-phenylacetic acid
(iv) $p$-methyl-phenylacetic acid

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What is the order of reactivity of the following compounds towards sodalime decarboxylation? $(i)$ $m$-nitro-phenylacetic acid (ii) $p$-nitro-phenylacetic acid (iii) $p$-methoxy-phenylacetic acid (iv) $p$-methyl-phenylacetic acid