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(B) The given qualitative analysis indicates the following properties of the compound:$1$. Insoluble in dilute $HCl$: This suggests the compound is no

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Phenol

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(B) The given qualitative analysis indicates the following properties of the compound:$1$. Insoluble in dilute $HCl$: This suggests the compound is not basic (like an amine).$2$. Soluble in $NaOH$ solution: This indicates the compound is acidic (like a phenol or carboxylic acid).$3$. Decolourization of $Br_2/	ext{water}$: This indicates the presence of an unsaturated system or a highly activated aromatic ring (like phenol,which forms $2,4,6-	ext{tribromophenol}$).Comparing these properties:- Cyclohexanol is neutral and does not dissolve in $NaOH$.- Phenol is acidic,dissolves in $NaOH$ to form sodium phenoxide,and reacts with bromine water to decolourise it.- Cyclohexylamine is basic and dissolves in $HCl$.- Aniline is basic and dissolves in $HCl$.Therefore,the compound is Phenol.

Test	Inference
$a$. Dil. $HCl$	Insoluble
$b$. $NaOH$ solution	Soluble
$c$. $Br_2/\text{water}$	Decolourization

The organic compound that gives the following qualitative analysis is:

Test Inference

$a$. Dil. $HCl$ Insoluble

$b$. $NaOH$ solution Soluble

$c$. $Br_2/\text{water}$ Decolourization

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The organic compound that gives the following qualitative analysis is: Test Inference $a$. Dil. $HCl$ Insoluble $b$. $NaOH$ solution Soluble $c$. $Br_2/\text{water}$ Decolourization