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(D) The given circuit consists of two $NOR$ gates whose outputs are fed into an $OR$ gate. Let the inputs be $A$ and $B$. The output of the top $NOR$

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$NOR$ gate

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(D) The given circuit consists of two $NOR$ gates whose outputs are fed into an $OR$ gate. Let the inputs be $A$ and $B$. The output of the top $NOR$ gate is $C = \overline{A+B}$ and the output of the bottom $NOR$ gate is $D = \overline{A+B}$. These are fed into an $OR$ gate,so the final output is $Y = C + D = \overline{A+B} + \overline{A+B} = \overline{A+B}$.The truth table for this combination is:$A$$B$$C = \overline{A+B}$$D = \overline{A+B}$$Y = C + D$$0$$0$$1$$1$$1$$0$$1$$0$$0$$0$$1$$0$$0$$0$$0$$1$$1$$0$$0$$0$Comparing this with the truth table of standard logic gates,the output $Y$ is $1$ only when both $A$ and $B$ are $0$,which is the characteristic behavior of a $NOR$ gate.

The output of the following combination is the same as that of:

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The given truth table is correct for:
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Four $NOR$ gates are connected as shown in the figure. The truth table for the given figure is:

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