The output power in a step-up transformer used in practice is . . . . . .

$A$ transformer has $120$ turns in the primary coil and carries $5 \text{ A}$ current. Input power is $1 \text{ kW}$. To have $560 \text{ V}$ output, the number of turns in the secondary coil will be:

$A$ step-up transformer connected to a $220 \,V$ $AC$ line is to supply $22 \,kV$ for a neon sign in the secondary circuit. In the primary circuit,a fuse wire is connected which is to blow when the current in the secondary circuit exceeds $10 \,mA$. The turns ratio of the transformer is:

The coils of a step-down transformer have $500$ and $5000$ turns. In the primary coil, an $AC$ current of $4 \,A$ at $2200 \,V$ is sent. The value of the current and potential difference in the secondary coil is:

An $AC$ source of internal resistance $10^3 \Omega$ is connected to a transformer. The ratio of the number of turns in the primary to the number of turns in the secondary to match the source to a load resistance of $10 \Omega$ is

Explain the use of a transformer for the distribution of power over long distances.