The oxidation number of Cr in K_3CrO_8 is +5. | vedclass

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(A) The oxidation state of $Cr$ in $K_3CrO_8$ is given as $+5$. $Cr$ belongs to group $6$,so its maximum possible oxidation state is $+6$. The number

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(A) The oxidation state of $Cr$ in $K_3CrO_8$ is given as $+5$. $Cr$ belongs to group $6$,so its maximum possible oxidation state is $+6$. The number of peroxy linkages can be calculated using the formula: $	ext{Number of peroxy linkages} = \frac{	ext{Theoretical Oxidation State} - 	ext{Actual Oxidation State}}{2}$ However,a more direct method for $K_3CrO_8$ (which is $K_3[Cr(O_2)_4]$) is to observe the structure. In $K_3[Cr(O_2)_4]$,the $Cr$ atom is bonded to $4$ peroxy groups $(O_2^{2-})$. Therefore,there are $4$ peroxy linkages present in the molecule.

The oxidation number of $Cr$ in $K_3CrO_8$ is $+5$. How many peroxy linkages are present in this molecule?

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