(B) Barium peroxide is represented as $BaO_2$.In peroxides, the oxidation state of oxygen is $-1$.Let the oxidation number of $Ba$ be $x$.For the neut

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(B) Barium peroxide is represented as $BaO_2$.In peroxides, the oxidation state of oxygen is $-1$.Let the oxidation number of $Ba$ be $x$.For the neutral molecule $BaO_2$, the sum of oxidation numbers is $0$:$x + 2(-1) = 0$$x - 2 = 0$$x = +2$.Thus, the oxidation number of $Ba$ is $+2$.