The oxidation number of carbon in $CH_2Cl_2$ is

What is the oxidation state of $S$ in $H_2SO_3$?

Oxidation number of nitrogen in $NaNO_2$ is

$3 \ mole$ of $N_2H_4$ loses $30 \ mole$ of electrons to form a new compound. Calculate the oxidation state of $N$ in the new compound,assuming the oxidation state of $H$ remains unchanged.

Match the following Column-$I$ to Column-$II$ based on the oxidation state of the underlined nitrogen atom:

Column-$I$	Column-$II$
$A$. $\underline{N}H_4 Cl$	$P$. $+1$
$B$. $H\underline{N}O_3$	$Q$. $+5$
$C$. $\underline{N}_2 O$	$R$. $-3$
$D$. $\underline{N}H_2 OH$	$S$. $-1$

In the following reaction,assign the state for the underlined atom in the product of complete hydrolysis at $R.T.$:
$\underline{Cl_2}O + H_2O \longrightarrow 2HClO$