The oxidation number of cobalt in $K[Co(CO)_4]$ is
$(i)$ $+1$ $(ii)$ $+3$ $(iii)$ $-1$ $(iv)$ $-3$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(C) We know that $CO$ is a neutral ligand and $K$ carries a charge of $+1$.
Therefore,the complex can be written as $K^{+}[Co(CO)_4]^{-}$.
Let the oxidation number of $Co$ be $x$.
For the complex ion $[Co(CO)_4]^{-}$,the sum of oxidation numbers is equal to the charge on the ion:
$x + 4(0) = -1$
$x = -1$
Therefore,the oxidation number of $Co$ in the given complex is $-1$. Hence,option $(iii)$ is correct.

Explore More

Similar Questions

The $IUPAC$ name for $K[Ag(CN)_2]$ is:

What is the formula for the coordination compound triamminediaquachloridocobalt$(III)$ chloride?

The oxidation number of iron in the compound $K_4[Fe(CN)_6]$ is

The formula of the complex $Tris(ethylenediamine)cobalt(III)$ sulphate is:

The oxidation state and coordination number of $Cr$ in $K_3[Cr(C_2O_4)_3]$ are respectively:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo