The oxidation state of Co in K[Co(CO)_4] is | vedclass

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Question

(D) In the complex $K[Co(CO)_4]$,the potassium ion $K^+$ has an oxidation state of $+1$. Let the oxidation state of $Co$ be $x$. The carbonyl ligand $

Vedclass · Accepted Answer

$-1$

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(D) In the complex $K[Co(CO)_4]$,the potassium ion $K^+$ has an oxidation state of $+1$. Let the oxidation state of $Co$ be $x$. The carbonyl ligand $(CO)$ is neutral,so its oxidation state is $0$. The sum of oxidation states in the complex ion $[Co(CO)_4]^-$ must equal the charge on the ion,which is $-1$. Therefore,$x + 4(0) = -1$,which gives $x = -1$. Thus,the oxidation state of $Co$ is $-1$.

The oxidation state of $Co$ in $K[Co(CO)_4]$ is

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