(A) The complex compound $[Co(NH_3)_6]Cl_3$ dissociates as $[Co(NH_3)_6]Cl_3 \to [Co(NH_3)_6]^{3+} + 3Cl^-$.Let the oxidation state of $Co$ be $x$.The

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(A) The complex compound $[Co(NH_3)_6]Cl_3$ dissociates as $[Co(NH_3)_6]Cl_3 \to [Co(NH_3)_6]^{3+} + 3Cl^-$.Let the oxidation state of $Co$ be $x$.The oxidation state of the neutral ligand $NH_3$ is $0$.Therefore,$x + 6(0) = +3$,which gives $x = +3$.Thus,the oxidation state of cobalt is $+3$.