(C) In $Na_{2}O_{2}$,sodium $(Na)$ is in the $+1$ oxidation state. Let the oxidation state of oxygen be $x$. Since the molecule is neutral,the sum of

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(C) In $Na_{2}O_{2}$,sodium $(Na)$ is in the $+1$ oxidation state. Let the oxidation state of oxygen be $x$. Since the molecule is neutral,the sum of oxidation states is zero: $2(+1) + 2(x) = 0$. $2 + 2x = 0$ $2x = -2$ $x = -1$. Therefore,each oxygen atom in $Na_{2}O_{2}$ has an oxidation state of $-1$.