The oxide,which is best soluble in $H_2O$ is

  • A
    $Ba(OH)_2$
  • B
    $Mg(OH)_2$
  • C
    $Be(OH)_2$
  • D
    $Ca(OH)_2$

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Assertion : Both $Be$ and $Al$ can form complexes such as $BeF_4^{2-}$ and $AlF_6^{3-}$ respectively,$BeF_6^{3-}$ is not formed.
Reason : In case of $Be$,no vacant $d-$ orbitals are present in its outermost shell.

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