The oxide that gives H_{2}O_{2} most readily | vedclass

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(B) $1.$ $PbO_{2}$ does not react with water to give $H_{2}O_{2}$.$2.$ $Na_{2}O_{2} + 2 H_{2}O \rightarrow 2 NaOH + H_{2}O_{2}$. This reaction occurs

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$Na_{2}O_{2}$

Vedclass · Answer

(B) $1.$ $PbO_{2}$ does not react with water to give $H_{2}O_{2}$.$2.$ $Na_{2}O_{2} + 2 H_{2}O \rightarrow 2 NaOH + H_{2}O_{2}$. This reaction occurs readily at room temperature.$3.$ $SnO_{2}$ is an acidic oxide and does not yield $H_{2}O_{2}$ with water.$4.$ $BaO_{2} \cdot 8 H_{2}O$ requires the addition of a dilute acid (like $H_{2}SO_{4}$) to produce $H_{2}O_{2}$,not just water.

The oxide that gives $H_{2}O_{2}$ most readily on treatment with $H_{2}O$ is:

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