The pair of ions with paramagnetic nature and | vedclass

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Question

(C) To determine the correct pair,we analyze the electronic configuration and number of electrons for each ion:$1$. $Lu^{3+}$ $(Z=71)$: $[Xe] 4f^{14}$

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$Eu^{2+}, Gd^{3+}$

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(C) To determine the correct pair,we analyze the electronic configuration and number of electrons for each ion:$1$. $Lu^{3+}$ $(Z=71)$: $[Xe] 4f^{14}$,electrons = $68$,diamagnetic.$2$. $Yb^{2+}$ $(Z=70)$: $[Xe] 4f^{14}$,electrons = $68$,diamagnetic.$3$. $Eu^{3+}$ $(Z=63)$: $[Xe] 4f^{6}$,electrons = $60$,paramagnetic.$4$. $Pm^{2+}$ $(Z=61)$: $[Xe] 4f^{5}$,electrons = $59$,paramagnetic.$5$. $Eu^{2+}$ $(Z=63)$: $[Xe] 4f^{7}$,electrons = $61$,paramagnetic.$6$. $Gd^{3+}$ $(Z=64)$: $[Xe] 4f^{7}$,electrons = $61$,paramagnetic.$7$. $La^{3+}$ $(Z=57)$: $[Xe]$,electrons = $54$,diamagnetic.$8$. $Ce^{4+}$ $(Z=58)$: $[Xe]$,electrons = $54$,diamagnetic.Comparing the options,$Eu^{2+}$ and $Gd^{3+}$ both have $61$ electrons and both possess $7$ unpaired electrons in the $4f$ orbital,making them paramagnetic.

The pair of ions with paramagnetic nature and same number of electrons is

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