The pair of lanthanoid ions which are diamagn | vedclass

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(D) substance is diamagnetic if it has no unpaired electrons $(n = 0)$.Electronic configurations of the given ions:$Ce^{4+} \Rightarrow [Xe] 4f^0$ (No

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$Ce^{4+}$ and $Yb^{2+}$

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(D) substance is diamagnetic if it has no unpaired electrons $(n = 0)$.Electronic configurations of the given ions:$Ce^{4+} \Rightarrow [Xe] 4f^0$ (No unpaired electrons,diamagnetic)$Yb^{2+} \Rightarrow [Xe] 4f^{14}$ (All electrons paired,diamagnetic)$Ce^{3+} \Rightarrow [Xe] 4f^1$ (One unpaired electron,paramagnetic)$Eu^{2+} \Rightarrow [Xe] 4f^7$ (Seven unpaired electrons,paramagnetic)$Gd^{3+} \Rightarrow [Xe] 4f^7$ (Seven unpaired electrons,paramagnetic)$Eu^{3+} \Rightarrow [Xe] 4f^6$ (Six unpaired electrons,paramagnetic)$Pm^{3+} \Rightarrow [Xe] 4f^4$ (Four unpaired electrons,paramagnetic)$Sm^{3+} \Rightarrow [Xe] 4f^5$ (Five unpaired electrons,paramagnetic)Thus,the pair $Ce^{4+}$ and $Yb^{2+}$ is diamagnetic.

The pair of lanthanoid ions which are diamagnetic is

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