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(B) The given equation of the pair of straight lines is $3x^2 - 8xy + 5y^2 = 0$. Factoring this,we get $3x^2 - 3xy - 5xy + 5y^2 = 0$,which simplifies

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$(5x + 3y - 11)(x + y - 3) = 0$

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(B) The given equation of the pair of straight lines is $3x^2 - 8xy + 5y^2 = 0$. Factoring this,we get $3x^2 - 3xy - 5xy + 5y^2 = 0$,which simplifies to $3x(x - y) - 5y(x - y) = 0$,or $(3x - 5y)(x - y) = 0$. Thus,the individual lines are $L_1: 3x - 5y = 0$ and $L_2: x - y = 0$. $A$ line perpendicular to $ax + by + c = 0$ is of the form $bx - ay + k = 0$. For $L_1: 3x - 5y = 0$,the perpendicular line is $5x + 3y + k_1 = 0$. Since it passes through $(1, 2)$,$5(1) + 3(2) + k_1 = 0 \implies 5 + 6 + k_1 = 0 \implies k_1 = -11$. So,$5x + 3y - 11 = 0$. For $L_2: x - y = 0$,the perpendicular line is $x + y + k_2 = 0$. Since it passes through $(1, 2)$,$1 + 2 + k_2 = 0 \implies k_2 = -3$. So,$x + y - 3 = 0$. The combined equation is $(5x + 3y - 11)(x + y - 3) = 0$.

The pair of straight lines that passes through the point $(1, 2)$ and is perpendicular to the pair of straight lines $3x^2 - 8xy + 5y^2 = 0$ is:

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