The pair(s) of reagents that yield paramagnet | vedclass

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(D) . $Na$ in excess $NH_3$ forms solvated electrons,which are paramagnetic.$B$. $K + O_2$ (excess) $\rightarrow KO_2$. The superoxide ion $O_2^-$ has

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$A, B, C$

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(D) . $Na$ in excess $NH_3$ forms solvated electrons,which are paramagnetic.$B$. $K + O_2$ (excess) $\rightarrow KO_2$. The superoxide ion $O_2^-$ has one unpaired electron,making it paramagnetic.$C$. $Cu +$ dilute $HNO_3 \rightarrow Cu(NO_3)_2 + NO + H_2O$. $NO$ (nitric oxide) has an odd number of electrons $(15)$,making it paramagnetic.$D$. $O_2 + 2-ethylanthraquinol \rightarrow 2-ethylanthraquinone + H_2O_2$. $H_2O_2$ is diamagnetic.Therefore,the reagents yielding paramagnetic species are $A, B,$ and $C$.

Column-$I$	Column-$II$
$I. Ca(OH)_2$	$A$. Casts of statues
$II. NaCl$	$B$. White wash
$III. CaSO_4 \cdot \frac{1}{2}H_2O$	$C$. Antacid
$IV. CaCO_3$	$D$. Washing soda preparation

Column-$I$	Column-$II$
$A$. $Li$	$1$. Insoluble sulphate
$B$. $Na$	$2$. Strongest monoacidic base
$C$. $Ca$	$3$. Most negative $E^{\circ}$ cell value among alkali metals
$D$. $Ba$	$4$. Insoluble oxalate
	$5$. $6s^2$ outer electronic configuration

The pair$(s)$ of reagents that yield paramagnetic species is/are:
$A$. $Na$ and excess of $NH_3$
$B$. $K$ and excess of $O_2$
$C$. $Cu$ and dilute $HNO_3$
$D$. $O_2$ and $2-ethylanthraquinol$

Similar Questions

Which of the following alloys contains a non-metal?

Match the following compounds (Column-$I$) with their uses (Column-$II$):

Column-$I$ Column-$II$

$I. Ca(OH)_2$ $A$. Casts of statues

$II. NaCl$ $B$. White wash

$III. CaSO_4 \cdot \frac{1}{2}H_2O$ $C$. Antacid

$IV. CaCO_3$ $D$. Washing soda preparation

Select the correct statement$(s)$.

Select the correct statement.

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The pair$(s)$ of reagents that yield paramagnetic species is/are:$A$. $Na$ and excess of $NH_3$$B$. $K$ and excess of $O_2$$C$. $Cu$ and dilute $HNO_3$$D$. $O_2$ and $2-ethylanthraquinol$