The percent dissociation of a weak monobasic acid is $3 \%$ in its $0.02 \ M$ solution. What is the dissociation constant of the acid?
- A$9 \times 10^{-4}$
- B$3 \times 10^{-2}$
- C$2 \times 10^{-2}$
- D$1.8 \times 10^{-5}$
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View SolutionCalculate the molar concentration of a weak monobasic acid if the acid dissociation constant $K_a = 1.8 \times 10^{-5}$ and the degree of dissociation $\alpha = 0.01$.
DifficultMHT CET 2026
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