The percentage of nitrogen in urea is about: | vedclass

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(A) Step $1$: The chemical formula of urea is $NH_2CONH_2$.Step $2$: The molar mass of urea is $(2 	imes 14) + (4 	imes 1) + 12 + 16 = 60 \ 	ext{g/

Vedclass · Accepted Answer

$47$

Vedclass · Answer

(A) Step $1$: The chemical formula of urea is $NH_2CONH_2$.Step $2$: The molar mass of urea is $(2 	imes 14) + (4 	imes 1) + 12 + 16 = 60 \ 	ext{g/mol}$.Step $3$: There are $2$ nitrogen atoms in one molecule of urea, so the mass of nitrogen is $2 	imes 14 = 28 \ 	ext{g}$.Step $4$: The percentage of nitrogen is calculated as $\frac{	ext{mass of nitrogen}}{	ext{molar mass of urea}} 	imes 100 = \frac{28}{60} 	imes 100 = 46.66\%$.Step $5$: Rounding to the nearest whole number, we get approximately $47\%$.

The percentage of nitrogen in urea is about: (in $\%$)

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