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(A) Let the side of the square be $x$ and the radius of the circle be $r$.According to the problem,the perimeter of the circle is equal to the perimet

Vedclass · Accepted Answer

$14: 11$

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(A) Let the side of the square be $x$ and the radius of the circle be $r$.According to the problem,the perimeter of the circle is equal to the perimeter of the square:$2 \pi r = 4x$$x = \frac{\pi r}{2}$Now,we compare the area of the circle $(A_c = \pi r^2)$ to the area of the square $(A_s = x^2)$:$\frac{A_c}{A_s} = \frac{\pi r^2}{x^2} = \frac{\pi r^2}{(\frac{\pi r}{2})^2} = \frac{\pi r^2}{\frac{\pi^2 r^2}{4}}$$\frac{A_c}{A_s} = \frac{4}{\pi} = \frac{4}{22/7} = \frac{4 	imes 7}{22} = \frac{28}{22} = \frac{14}{11}$Thus,the ratio of their areas is $14: 11$.

The perimeter of a circle is equal to that of a square. Compare their areas.

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