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(A) Perimeter of the rectangle $= 2 	imes (8 + 7) = 2 	imes 15 = 30 \, cm$.Perimeter of the square $= 2 	imes 30 = 60 \, cm$.Side of the square $=

Vedclass · Accepted Answer

$38.57$

Vedclass · Answer

(A) Perimeter of the rectangle $= 2 	imes (8 + 7) = 2 	imes 15 = 30 \, cm$.Perimeter of the square $= 2 	imes 30 = 60 \, cm$.Side of the square $= 60 / 4 = 15 \, cm$.The diameter of the semicircle is equal to the side of the square,so $d = 15 \, cm$,which means the radius $r = 7.5 \, cm$.The circumference of a semicircle is given by the formula $C = \pi r + d$.$C = (22 / 7) 	imes 7.5 + 15$.$C = 23.5714 + 15 = 38.5714 \, cm$.Rounding to two decimal places,we get $38.57 \, cm$.

The perimeter of a square is equal to twice the perimeter of a rectangle whose dimensions are: length $8 \, cm$ and breadth $7 \, cm$. What is the circumference of a semicircle whose diameter is equal to the side of the square? (in $cm$) (Rounded off to two decimal places)

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