(A) दिया गया है: आवर्तकाल $T = 4 \times 10^{-10} \ s$। आवृत्ति $\nu = \frac{1}{T} = \frac{1}{4 \times 10^{-10}} = 0.25 \times 10^{10} = 2.5 \times 10^

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$\nu = 2.5 \times 10^{9} \ Hz, \lambda = 0.12 \ m, \bar{\nu} = 8.33 \ m^{-1}$

(A) दिया गया है: आवर्तकाल $T = 4 \times 10^{-10} \ s$। आवृत्ति $\nu = \frac{1}{T} = \frac{1}{4 \times 10^{-10}} = 0.25 \times 10^{10} = 2.5 \times 10^{9} \ Hz$। तरंगदैर्ध्य $\lambda = c \times T = (3 \times 10^{8} \ m/s) \times (4 \times 10^{-10} \ s) = 12 \times 10^{-2} \ m = 0.12 \ m$। तरंग संख्या $\bar{\nu} = \frac{1}{\lambda} = \frac{1}{0.12} = 8.33 \ m^{-1}$।

Class 11 Chemistry Structure of Atom Nature of radiation

Medium

विकिरण का आवर्तकाल $4 \times 10^{-10} \ s$ है। तरंगदैर्ध्य,तरंग संख्या और आवृत्ति ज्ञात कीजिए।

A
$\nu = 2.5 \times 10^{9} \ Hz, \lambda = 0.12 \ m, \bar{\nu} = 8.33 \ m^{-1}$
B
$\nu = 2.5 \times 10^{8} \ Hz, \lambda = 0.12 \ m, \bar{\nu} = 8.33 \ m^{-1}$
C
$\nu = 2.5 \times 10^{9} \ Hz, \lambda = 0.12 \ m, \bar{\nu} = 8.33 \ cm^{-1}$
D
$\nu = 2.5 \times 10^{10} \ Hz, \lambda = 0.12 \ m, \bar{\nu} = 8.33 \ m^{-1}$