The phase angle between e.m.f. and current in | vedclass

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Question

(A) In an $LCR$ series $ac$ circuit,the phase difference $\phi$ between the applied voltage $V$ and the current $i$ is given by $	an \phi = \frac{X_L

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$0$ to $\pi/2$

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(A) In an $LCR$ series $ac$ circuit,the phase difference $\phi$ between the applied voltage $V$ and the current $i$ is given by $	an \phi = \frac{X_L - X_C}{R}$.If $X_L > X_C$,the circuit is inductive,and the phase angle $\phi$ lies between $0$ and $\pi/2$ (current lags behind voltage).If $X_L If $X_L = X_C$,the circuit is at resonance,and $\phi = 0$.Therefore,the magnitude of the phase angle $|\phi|$ ranges from $0$ to $\pi/2$ depending on the values of $X_L$ and $X_C$.

The phase angle between $e.m.f.$ and current in an $LCR$ series $ac$ circuit is:

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