The plane of a dip circle is set in the geogr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let $\phi$ be the true dip angle and $	heta$ be the magnetic declination. When the dip circle is in the geographic meridian,the angle between the

Vedclass · Accepted Answer

$	an ^{-1}(\frac{	an \delta_1}{	an \delta_2})$

Vedclass · Answer

(C) Let $\phi$ be the true dip angle and $	heta$ be the magnetic declination. When the dip circle is in the geographic meridian,the angle between the plane and the magnetic meridian is $	heta$. The apparent dip $\delta_1$ is given by $	an \delta_1 = \frac{	an \phi}{\cos 	heta}$.When the plane is perpendicular to the geographic meridian,the angle between the plane and the magnetic meridian is $(90^\circ - 	heta)$. The apparent dip $\delta_2$ is given by $	an \delta_2 = \frac{	an \phi}{\cos(90^\circ - 	heta)} = \frac{	an \phi}{\sin 	heta}$.From these two equations,we have $	an \phi = 	an \delta_1 \cos 	heta$ and $	an \phi = 	an \delta_2 \sin 	heta$.Equating the two expressions for $	an \phi$: $	an \delta_1 \cos 	heta = 	an \delta_2 \sin 	heta$.Rearranging gives $\frac{\sin 	heta}{\cos 	heta} = \frac{	an \delta_1}{	an \delta_2}$,which implies $	an 	heta = \frac{	an \delta_1}{	an \delta_2}$.Therefore,$	heta = 	an ^{-1}\left(\frac{	an \delta_1}{	an \delta_2}ight)$.

The plane of a dip circle is set in the geographic meridian and the apparent dip is $\delta_1$. It is then set in a vertical plane perpendicular to the geographic meridian. The apparent dip angle is $\delta_2$. The declination $\theta$ at the place is

Similar Questions

The angle of dip at a certain place is $30^o$. If the horizontal component of the earth's magnetic field is $H$,the intensity of the total magnetic field is:

The pole near the geographic north pole is called ...... . The pole near the geographic south pole is called ...... .

At a place,if the earth's horizontal and vertical components of magnetic fields are equal,then the angle of dip will be.......$^o$

The vertical component of the earth's magnetic field is $6 \times 10^{-5} \text{ T}$ at a place where the angle of dip is $37^{\circ}$. The earth's resultant magnetic field at that place will be (Given $\tan 37^{\circ} = \frac{3}{4}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module