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(D) During the electrolysis of $CuSO_4$ using platinum electrodes,the following reactions occur: At the cathode: $Cu^{2+}(aq) + 2e^- \rightarrow Cu(s)

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Sulphuric acid

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(D) During the electrolysis of $CuSO_4$ using platinum electrodes,the following reactions occur: At the cathode: $Cu^{2+}(aq) + 2e^- \rightarrow Cu(s)$ At the anode: $2H_2O(l) \rightarrow O_2(g) + 4H^+(aq) + 4e^-$ As the $Cu^{2+}$ ions are removed from the solution to form copper metal at the cathode,the blue colour of the solution fades. The remaining ions in the solution are $H^+$ and $SO_4^{2-}$,which combine to form $H_2SO_4$ (sulphuric acid). Thus,the final colourless solution contains sulphuric acid.

The platinum electrodes were immersed in a solution of cupric sulphate and electric current was passed through the solution. After some time,it was found that the colour of copper sulphate disappeared with the evolution of gas at the electrode. The colourless solution contains:

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