The polar of (1, -2) with respect to x^2+y^2- | vedclass

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Question

(B) The equation of the circle is $x^2+y^2-10x-10y+25=0$. Given point $P$ is $(1, -2)$. The equation of the polar of a point $(x_1, y_1)$ with respect

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$4x+7y-30=0$

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(B) The equation of the circle is $x^2+y^2-10x-10y+25=0$. Given point $P$ is $(1, -2)$. The equation of the polar of a point $(x_1, y_1)$ with respect to the circle $x^2+y^2+2gx+2fy+c=0$ is given by $xx_1+yy_1+g(x+x_1)+f(y+y_1)+c=0$. Here,$g = -5$,$f = -5$,$c = 25$,$x_1 = 1$,and $y_1 = -2$. Substituting these values: $x(1) + y(-2) - 5(x+1) - 5(y-2) + 25 = 0$ $x - 2y - 5x - 5 - 5y + 10 + 25 = 0$ $-4x - 7y + 30 = 0$ Multiplying by $-1$,we get $4x + 7y - 30 = 0$.

The polar of $(1, -2)$ with respect to $x^2+y^2-10x-10y+25=0$ is

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