The population of a town 2 years ago was 6250 | vedclass

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(B) Population $2$ years ago $= 62500$.The population decreases at a rate of $4\%$ per year.Using the formula for depreciation: $	ext{Present Populat

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$57600$

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(B) Population $2$ years ago $= 62500$.The population decreases at a rate of $4\%$ per year.Using the formula for depreciation: $	ext{Present Population} = P \left(1 - \frac{R}{100}ight)^n$,where $P = 62500$,$R = 4$,and $n = 2$.$	ext{Present Population} = 62500 \left(1 - \frac{4}{100}ight)^2$$= 62500 \left(\frac{96}{100}ight)^2 = 62500 \left(\frac{24}{25}ight)^2$$= 62500 	imes \frac{576}{625} = 100 	imes 576 = 57600$.Thus,the present population of the town is $57600$.

The population of a town $2$ years ago was $62500$. Due to migration to big cities,it decreases every year at the rate of $4\%$. The present population of the town is:

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