The population of a town was 160000 three yea | vedclass

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(B) Population $3$ years ago $= 160000$. Present population $= 160000 	imes (1 + \frac{3}{100}) 	imes (1 + \frac{2.5}{100}) 	imes (1 + \frac{5}{100

Vedclass · Accepted Answer

$177366$

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(B) Population $3$ years ago $= 160000$. Present population $= 160000 	imes (1 + \frac{3}{100}) 	imes (1 + \frac{2.5}{100}) 	imes (1 + \frac{5}{100})$. Present population $= 160000 	imes \frac{103}{100} 	imes \frac{102.5}{100} 	imes \frac{105}{100}$. Present population $= 160000 	imes \frac{103}{100} 	imes \frac{205}{200} 	imes \frac{105}{100}$. Present population $= 16 	imes 103 	imes \frac{205}{2} 	imes \frac{21}{20} = 4 	imes 103 	imes 205 	imes \frac{21}{10}$. Present population $= 177366$.

The population of a town was $160000$ three years ago. If it increased by $3 \%$,$2.5 \%$,and $5 \%$ respectively in the last three years,then the present population is:

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