The possible number of stereoisomers for 5-ph | vedclass

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Question

(B) The structure of $5-$phenylpent$-4-$en$-2-$ol is $C_6H_5-CH=CH-CH_2-CH(OH)-CH_3$.
There are two stereogenic units in this molecule:
$1$. The car

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) The structure of $5-$phenylpent$-4-$en$-2-$ol is $C_6H_5-CH=CH-CH_2-CH(OH)-CH_3$.
There are two stereogenic units in this molecule:
$1$. The carbon-carbon double bond $(C=C)$ at position $4$,which can exhibit geometrical isomerism ($cis$ or $trans$).
$2$. The chiral carbon atom at position $2$,which can exhibit optical isomerism ($R$ or $S$ configuration).
Since the molecule does not have a plane of symmetry,the total number of stereoisomers is given by $2^n$,where $n$ is the number of stereogenic units.
Here,$n = 2$,so the number of stereoisomers $= 2^2 = 4$.

The possible number of stereoisomers for $5-$phenylpent$-4-$en$-2-$ol is $.............$

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