The electric potential at a point due to an e | vedclass

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Question

(D) The electric potential $V$ at a point due to an electric dipole is given by the formula: $V = \frac{kp \cos 	heta}{r^2}$, where $p$ is the dipole

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$0^\circ$ and $180^\circ$

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(D) The electric potential $V$ at a point due to an electric dipole is given by the formula: $V = \frac{kp \cos 	heta}{r^2}$, where $p$ is the dipole moment, $r$ is the distance from the center of the dipole, and $	heta$ is the angle between the dipole axis and the position vector of the point.For the potential to be maximum, $\cos 	heta$ must be maximum $(+1)$, which occurs at $	heta = 0^\circ$.For the potential to be minimum, $\cos 	heta$ must be minimum $(-1)$, which occurs at $	heta = 180^\circ$.Therefore, the potential is maximum at $0^\circ$ and minimum at $180^\circ$.

The electric potential at a point due to an electric dipole is maximum and minimum when the angles between the axis of the dipole and the line joining the point to the center of the dipole are respectively:

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