The potential energy of a body of mass m is g | vedclass

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(D) The force components are given by the negative gradient of the potential energy:$F_x = -\frac{\partial U}{\partial x} = -a$$F_y = -\frac{\partial

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$\frac{(a^2 + b^2)^{1/2}}{m}$

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(D) The force components are given by the negative gradient of the potential energy:$F_x = -\frac{\partial U}{\partial x} = -a$$F_y = -\frac{\partial U}{\partial y} = -b$The magnitude of the net force is $F = \sqrt{F_x^2 + F_y^2} = \sqrt{(-a)^2 + (-b)^2} = \sqrt{a^2 + b^2}$.Using Newton's second law,the acceleration $a_{acc}$ is given by $a_{acc} = \frac{F}{m} = \frac{\sqrt{a^2 + b^2}}{m} = \frac{(a^2 + b^2)^{1/2}}{m}$.

The potential energy of a body of mass $m$ is given by $U = ax + by$,where $x$ and $y$ are the position coordinates of the particle. The acceleration of the particle is

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