The power factor of the circuit as shown in t | vedclass

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(C) The total resistance of the circuit is the sum of the individual resistances:$R = R_{1} + R_{2} = 40 \, \Omega + 40 \, \Omega = 80 \, \Omega$The i

Vedclass · Accepted Answer

$0.8$

Vedclass · Answer

(C) The total resistance of the circuit is the sum of the individual resistances:$R = R_{1} + R_{2} = 40 \, \Omega + 40 \, \Omega = 80 \, \Omega$The impedance $Z$ of the $LCR$ series circuit is given by:$Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}}$Substituting the given values:$Z = \sqrt{(80)^{2} + (100 - 40)^{2}}$$Z = \sqrt{80^{2} + 60^{2}} = \sqrt{6400 + 3600} = \sqrt{10000} = 100 \, \Omega$The power factor of the circuit is defined as:$\cos \phi = \frac{R}{Z}$$\cos \phi = \frac{80}{100} = 0.8$

The power factor of the circuit as shown in the figure is:

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