The power is transmitted from a power house on high voltage $ac$ because

  • A
    Electric current travels faster at higher volts
  • B
    It is more economical due to less power wastage
  • C
    It is difficult to generate power at low voltage
  • D
    Chances of stealing transmission lines are minimized

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Similar Questions

In the circuit shown below,what will be the readings of the voltmeter and ammeter?

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Assertion: Long distance power transmission is done at high voltage.
Reason: At high voltage supply, power losses are less.

An initially charged undriven $LCR$ circuit having inductance $L$,capacitance $C$ and resistance $R$ will be:

In a series $LCR$ circuit,$R = 200 \, \Omega$ and the voltage and frequency of the main supply are $220 \, V$ and $50 \, Hz$ respectively. On taking out the capacitance from the circuit,the current lags behind the voltage by $30^\circ$. On taking out the inductor from the circuit,the current leads the voltage by $30^\circ$. The power dissipated in the $LCR$ circuit is......$W$.

$A$ circuit with an electrical load having impedance $Z$ is connected with an $AC$ source as shown in the diagram. The source voltage varies in time as $V(t) = 300 \sin (400 t) \text{ V}$,where $t$ is time in seconds. List-$I$ shows various options for the load. The possible currents $i(t)$ in the circuit as a function of time are given in List-$II$. Choose the option that describes the correct match between the entries in List-$I$ to those in List-$II$.
List-$I$ List-$II$
$(P)$ Resistor $R = 30 \ \Omega$ $(1)$ $i(t) = 5 \sin(400t)$
$(Q)$ Resistor $R = 30 \ \Omega$ and Inductor $L = 100 \text{ mH}$ $(2)$ $i(t) = 6 \sin(400t + 53^{\circ})$
$(R)$ Capacitor $C = 50 \ \mu\text{F}$,Resistor $R = 30 \ \Omega$,and Inductor $L = 25 \text{ mH}$ $(3)$ $i(t) = 10 \sin(400t)$
$(S)$ Capacitor $C = 50 \ \mu\text{F}$,Resistor $R = 60 \ \Omega$,and Inductor $L = 125 \text{ mH}$ $(4)$ $i(t) = 20 \sin(400t - 90^{\circ})$
$(5)$ $i(t) = 6 \sin(400t - 53^{\circ})$

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