The percentage of Se in peroxidase enzyme is | vedclass

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(A) To find the minimum molecular mass of the enzyme,we assume that it contains at least one atom of $Se$.Given that the percentage of $Se$ by mass is

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$1.568 	imes 10^4 \ amu$

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(A) To find the minimum molecular mass of the enzyme,we assume that it contains at least one atom of $Se$.Given that the percentage of $Se$ by mass is $0.5\%$ and the atomic mass of $Se$ is $78.4 \ amu$.The formula for minimum molecular mass is:$	ext{Minimum molecular mass} = \frac{	ext{Atomic mass of element} 	imes 100}{	ext{Percentage of element}}$Substituting the values:$	ext{Minimum molecular mass} = \frac{78.4 	imes 100}{0.5}$$= \frac{7840}{0.5}$$= 15680 \ amu$$= 1.568 	imes 10^4 \ amu$

The percentage of $Se$ in peroxidase enzyme is $0.5\%$ by mass (atomic mass of $Se = 78.4 \ amu$). Then,the minimum molecular mass of enzyme which contains not more than one $Se$ atom is

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