The pressure of a gas is 100 kPa. If it is c | vedclass

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(D) Given: Pressure $p = 100 \ kPa = 10^{5} \ Pa$.Initial volume $V_{1} = 1 \ m^{3}$.Final volume $V_{2} = 10 \ dm^{3} = 10 	imes 10^{-3} \ m^{3} = 0

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$99000$

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(D) Given: Pressure $p = 100 \ kPa = 10^{5} \ Pa$.Initial volume $V_{1} = 1 \ m^{3}$.Final volume $V_{2} = 10 \ dm^{3} = 10 	imes 10^{-3} \ m^{3} = 0.01 \ m^{3}$.Work done on the system is given by $W = -p_{ext} \Delta V = -p_{ext}(V_{2} - V_{1})$.Since the gas is compressed, work is done on the system, so $W = p_{ext}(V_{1} - V_{2})$.$W = 10^{5} \ Pa 	imes (1 \ m^{3} - 0.01 \ m^{3}) = 10^{5} 	imes 0.99 \ J = 99,000 \ J$.

The pressure of a gas is $100 \ kPa$. If it is compressed from $1 \ m^{3}$ to $10 \ dm^{3}$, find the work done on the system (in $J$).

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