The pressure of air in a soap bubble of 0.7 | vedclass

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(B) The excess pressure inside a soap bubble is given by $\Delta P = \frac{4T}{r}$.Given,diameter $d = 0.7 \ cm$,so radius $r = 0.35 \ cm$.Excess pres

Vedclass · Accepted Answer

$68.66$

Vedclass · Answer

(B) The excess pressure inside a soap bubble is given by $\Delta P = \frac{4T}{r}$.Given,diameter $d = 0.7 \ cm$,so radius $r = 0.35 \ cm$.Excess pressure $\Delta P = h ho g$,where $h = 8 \ mm = 0.8 \ cm$,$ho = 1 \ g/cm^3$,and $g = 980 \ cm/s^2$.$\Delta P = 0.8 	imes 1 	imes 980 = 784 \ dyne/cm^2$.Using $\Delta P = \frac{4T}{r}$,we get $T = \frac{\Delta P 	imes r}{4}$.$T = \frac{784 	imes 0.35}{4} = 196 	imes 0.35 = 68.6 \ dyne/cm$.Thus,the closest value is $68.66 \ dyne/cm$.

The pressure of air in a soap bubble of $0.7 \ cm$ diameter is $8 \ mm$ of water above the pressure outside. The surface tension of the soap solution is ........ $dyne/cm$.

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