The primary and secondary coils of a transfor | vedclass

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(C) The induced $emf$ in the primary coil is given by Faraday's law: $E_P = \frac{d\phi}{dt}$.Substituting the given flux $\phi = \phi_0 + 4t$,we get

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$120$

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(C) The induced $emf$ in the primary coil is given by Faraday's law: $E_P = \frac{d\phi}{dt}$.Substituting the given flux $\phi = \phi_0 + 4t$,we get $E_P = \frac{d}{dt}(\phi_0 + 4t) = 4 \, V$.For an ideal transformer,the ratio of the secondary voltage $E_S$ to the primary voltage $E_P$ is equal to the ratio of the number of turns in the secondary coil $N_S$ to the number of turns in the primary coil $N_P$.$\frac{E_S}{E_P} = \frac{N_S}{N_P}$.Given $N_P = 50$ and $N_S = 1500$,we have $\frac{E_S}{4} = \frac{1500}{50}$.$\frac{E_S}{4} = 30$.Therefore,$E_S = 30 	imes 4 = 120 \, V$.

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