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Question

(C) The complex is $K[Co(OX)_2(NH_3)_2]$.$1$. Primary valency is the oxidation state of the central metal ion $(Co)$. Let the oxidation state be $x$.

Vedclass · Accepted Answer

$3, 6, 2$

Vedclass · Answer

(C) The complex is $K[Co(OX)_2(NH_3)_2]$.$1$. Primary valency is the oxidation state of the central metal ion $(Co)$. Let the oxidation state be $x$. $1 + x + 2(-2) + 2(0) = 0$,so $x - 3 = 0$,which gives $x = +3$.$2$. Secondary valency is the coordination number. $OX$ is a bidentate ligand (coordination number $2$) and $NH_3$ is a monodentate ligand (coordination number $1$). Total coordination number = $(2 	imes 2) + (2 	imes 1) = 4 + 2 = 6$.$3$. In aqueous solution,the complex dissociates as: $K[Co(OX)_2(NH_3)_2] ightarrow K^+ + [Co(OX)_2(NH_3)_2]^-$. This produces $1 + 1 = 2$ ions.Thus,the values are $3, 6, 2$.

The primary valency and secondary valency of the central metal ion and the number of total ions produced in an aqueous solution for the $K[Co(OX)_2(NH_3)_2]$ complex are,respectively, . . . . . . .

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