The principal product of the reaction between | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Methyl butanoate $(C_3H_7COOCH_3)$ reacts with the first mole of $CH_3MgBr$ to form a ketone,$2$-pentanone $(C_3H_7COCH_3)$,by displacing the meth

Vedclass · Accepted Answer

$C_3H_7-C(OH)(CH_3)_2$

Vedclass · Answer

(B) Methyl butanoate $(C_3H_7COOCH_3)$ reacts with the first mole of $CH_3MgBr$ to form a ketone,$2$-pentanone $(C_3H_7COCH_3)$,by displacing the methoxy group $(-OCH_3)$.This ketone then reacts with the second mole of $CH_3MgBr$ to form an alkoxide intermediate.Upon acidic hydrolysis,the alkoxide intermediate yields the tertiary alcohol,$2$-methylpentan-$2$-ol $(C_3H_7C(OH)(CH_3)_2)$.

The principal product of the reaction between methyl butanoate and $2$ moles of $CH_3MgBr$ after hydrolysis is

Similar Questions

In the given reaction sequence,the conversion of $B$ to $C$ is known as:

Which of the following compounds will not show tautomerism?

Which of the following reactions is used to detect the presence of a carbonyl group?

In the given transformation,which of the following is the most appropriate reagent?

The correct order of reactivity of $PhMgBr$ with:
$(I)$ $Ph-CO-Ph$
$(II)$ $CH_3-CHO$
$(III)$ $CH_3-CO-CH_3$
is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module