The probability of a leap year having 53 Wedn | vedclass

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Question

(D) leap year consists of $366$ days.$366$ days = $52$ weeks and $2$ extra days.The $2$ extra days can be any of the following pairs: (Sunday,Monday),

Vedclass · Accepted Answer

$\frac{2}{7}$

Vedclass · Answer

(D) leap year consists of $366$ days.$366$ days = $52$ weeks and $2$ extra days.The $2$ extra days can be any of the following pairs: (Sunday,Monday),(Monday,Tuesday),(Tuesday,Wednesday),(Wednesday,Thursday),(Thursday,Friday),(Friday,Saturday),(Saturday,Sunday).There are $7$ possible outcomes for these $2$ extra days.For a leap year to have $53$ Wednesdays,one of the $2$ extra days must be a Wednesday.From the list above,the pairs containing Wednesday are (Tuesday,Wednesday) and (Wednesday,Thursday).Thus,there are $2$ favorable outcomes.Therefore,the required probability = $\frac{2}{7}$.

The probability of a leap year having $53$ Wednesdays is ...........

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