(D) Given: $P(A \cup B) = 0.6$ and $P(A \cap B) = 0.2$.Using the formula $P(A \cup B) = P(A) + P(B) - P(A \cap B)$:$0.6 = P(A) + P(B) - 0.2$$P(A) + P(

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(D) Given: $P(A \cup B) = 0.6$ and $P(A \cap B) = 0.2$.Using the formula $P(A \cup B) = P(A) + P(B) - P(A \cap B)$:$0.6 = P(A) + P(B) - 0.2$$P(A) + P(B) = 0.8$We know that $P(\overline{A}) = 1 - P(A)$ and $P(\overline{B}) = 1 - P(B)$.Therefore, $P(\overline{A}) + P(\overline{B}) = (1 - P(A)) + (1 - P(B)) = 2 - (P(A) + P(B))$.Substituting the value: $2 - 0.8 = 1.2$.

Class 11 Mathematics Probability Set Based probability

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The probability of at least one of the events $A$ and $B$ occurring is $0.6$. If $A$ and $B$ occur simultaneously with probability $0.2$, then $P(\overline{A}) + P(\overline{B})$ is

KCET 2026 All KCET

A
$1$
B
$0.8$
C
$0.6$
D
$1.2$

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The probability of at least one of the events $A$ and $B$ occurring is $0.6$. If $A$ and $B$ occur simultaneously with probability $0.2$, then $P(\overline{A}) + P(\overline{B})$ is

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