The probability that a marksman will hit a ta | vedclass

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(A) Let $p$ be the probability of hitting the target,so $p = 1/5$.Let $q$ be the probability of missing the target,so $q = 1 - p = 1 - 1/5 = 4/5$.For

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$1 - (4/5)^{10}$

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(A) Let $p$ be the probability of hitting the target,so $p = 1/5$.Let $q$ be the probability of missing the target,so $q = 1 - p = 1 - 1/5 = 4/5$.For $n = 10$ shots,the probability of hitting the target zero times is given by the binomial distribution formula $P(X = 0) = q^n = (4/5)^{10}$.The probability of at least one hit is $P(X \ge 1) = 1 - P(X = 0)$.Therefore,$P(X \ge 1) = 1 - (4/5)^{10}$.

The probability that a marksman will hit a target is given as $1/5$. Then his probability of at least one hit in $10$ shots is:

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