The product(s) obtained via oxymercuration (H | vedclass

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(A) The hydration of terminal alkynes like $but-1-yne$ in the presence of $HgSO_4$ and $H_2SO_4$ follows Markovnikov's rule.Step $1$: The alkyne react

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$CH_3CH_2COCH_3$

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(A) The hydration of terminal alkynes like $but-1-yne$ in the presence of $HgSO_4$ and $H_2SO_4$ follows Markovnikov's rule.Step $1$: The alkyne reacts with water to form an unstable enol intermediate: $CH_3-CH_2-C \equiv CH + H_2O \xrightarrow{HgSO_4/H_2SO_4} [CH_3-CH_2-C(OH)=CH_2]$.Step $2$: The enol undergoes tautomerization to form a stable ketone: $[CH_3-CH_2-C(OH)=CH_2] \rightarrow CH_3-CH_2-COCH_3$ $(Butan-2-one)$.Therefore,the correct product is $Butan-2-one$.

The product$(s)$ obtained via oxymercuration $(HgSO_4 + H_2SO_4)$ of $but-1-yne$ would be

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